sql server 2008 r2中，無法刪除對象 'print_template'，因?yàn)樵搶ο笳梢粋€ FOREIGN KEY 約束引用。

-- 1. 首先找出哪些表引用了 print_template
SELECT 
    fk.name AS ForeignKeyName,
    OBJECT_NAME(fk.parent_object_id) AS ReferencingTable
FROM 
    sys.foreign_keys fk
WHERE 
    OBJECT_NAME(fk.referenced_object_id) = 'print_template'

-- 2. 刪除找到的外鍵約束
ALTER TABLE [引用表的名稱] DROP CONSTRAINT [外鍵約束名稱]

-- 3. 然后就可以刪除 print_template 表了
DROP TABLE print_template

-- 直接刪除外鍵約束（如果你知道約束名稱）
ALTER TABLE [其他表名] DROP CONSTRAINT FK_約束名

-- 然后刪除表
DROP TABLE print_template

-- 查看完整的外鍵關(guān)系信息
EXEC sp_fkeys @fktable_name = 'print_template'

-- 或者查看所有引用此表的外鍵
SELECT 
    obj.name AS FK_NAME,
    sch.name AS [schema_name],
    tab1.name AS [table],
    col1.name AS [column],
    tab2.name AS [referenced_table],
    col2.name AS [referenced_column]
FROM 
    sys.foreign_key_columns fkc
    INNER JOIN sys.objects obj ON obj.object_id = fkc.constraint_object_id
    INNER JOIN sys.tables tab1 ON tab1.object_id = fkc.parent_object_id
    INNER JOIN sys.schemas sch ON tab1.schema_id = sch.schema_id
    INNER JOIN sys.columns col1 ON col1.column_id = fkc.parent_column_id AND col1.object_id = tab1.object_id
    INNER JOIN sys.tables tab2 ON tab2.object_id = fkc.referenced_object_id
    INNER JOIN sys.columns col2 ON col2.column_id = fkc.referenced_column_id AND col2.object_id = tab2.object_id
WHERE 
    tab2.name = 'print_template'

-- 生成刪除所有引用此外鍵的腳本
DECLARE @sql NVARCHAR(MAX) = ''

SELECT @sql = @sql + 'ALTER TABLE ' + QUOTENAME(OBJECT_SCHEMA_NAME(fk.parent_object_id)) 
    + '.' + QUOTENAME(OBJECT_NAME(fk.parent_object_id)) 
    + ' DROP CONSTRAINT ' + QUOTENAME(fk.name) + ';' + CHAR(13)
FROM sys.foreign_keys fk
WHERE OBJECT_NAME(fk.referenced_object_id) = 'print_template'

PRINT @sql  -- 先查看生成的腳本
-- EXEC sp_executesql @sql  -- 確認(rèn)無誤后執(zhí)行

-- 最后刪除表
-- DROP TABLE print_template

-- 重建約束時使用級聯(lián)刪除
ALTER TABLE [子表名] 
ADD CONSTRAINT FK_名稱 
FOREIGN KEY (列名) 
REFERENCES print_template(列名)
ON DELETE CASCADE