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一列保存多個(gè)ID(將多個(gè)用逗號(hào)隔開(kāi)的ID轉(zhuǎn)換成用逗號(hào)隔開(kāi)的名稱)

更新時(shí)間：2012年07月27日 11:04:30 作者：

在做項(xiàng)目時(shí)，經(jīng)常會(huì)遇到這樣的表結(jié)構(gòu)在主表的中有一列保存的是用逗號(hào)隔開(kāi)ID

背景：在做項(xiàng)目時(shí)，經(jīng)常會(huì)遇到這樣的表結(jié)構(gòu)在主表的中有一列保存的是用逗號(hào)隔開(kāi)ID。如，當(dāng)一個(gè)員工從屬多個(gè)部門時(shí)、當(dāng)一個(gè)項(xiàng)目從屬多個(gè)城市時(shí)、當(dāng)一個(gè)設(shè)備從屬多個(gè)項(xiàng)目時(shí)，很多人都會(huì)在員工表中加入一個(gè)deptIds VARCHAR(1000)列（本文以員工從屬多個(gè)部門為例），用以保存部門編號(hào)列表（很明顯這不符合第一范式，但很多人這樣設(shè)計(jì)了，在這篇文章中我們暫不討論在這種應(yīng)用場(chǎng)景下，如此設(shè)計(jì)的對(duì)與錯(cuò)，有興趣的可以在回復(fù)中聊聊），然后我們?cè)诓樵兞斜碇行枰吹竭@個(gè)員工從屬哪些部門。
初始化數(shù)據(jù)：
部門表、員工表數(shù)據(jù)：

復(fù)制代碼代碼如下:

 

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Department]')) 
DROP TABLE [dbo].Department 
GO 
--部門表 
CREATE TABLE Department 
( 
id int, 
name nvarchar(50) 
) 
INSERT INTO Department(id,name) 
SELECT 1,'人事部' 
UNION 
SELECT 2,'工程部' 
UNION 
SELECT 3,'管理部' 
SELECT * FROM Department 

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Employee]')) 
DROP TABLE [dbo].Employee 
GO 
--員工表 
CREATE TABLE Employee 
( 
id int, 
name nvarchar(20), 
deptIds varchar(1000) 
) 
INSERT INTO Employee(id,name,deptIds) 
SELECT 1,'蔣大華','1,2,3' 
UNION 
SELECT 2,'小明','1' 
UNION 
SELECT 3,'小華','' 
SELECT * FROM Employee 

希望得到的結(jié)果：

解決方法：

第一步，是得到如下的數(shù)據(jù)。即將員工表集合與相關(guān)的部門集合做交叉連接，其中使用了fun_SplitIds函數(shù)（作用是將ids分割成id列表），然后員工集合與這個(gè)得到的集合做交叉連接

復(fù)制代碼代碼如下:

 
SELECT E.*,ISNULL(D.name,'') AS deptName 
FROM Employee AS E 
OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID 
LEFT JOIN Department AS D ON DID.ID=D.id; 

第二步，已經(jīng)得到了如上的數(shù)據(jù)，然后要做的就是根據(jù)ID分組，并對(duì)deptName列做聚合操作，但可惜的是SQL SERVER還沒(méi)有提供對(duì)字符串做聚合的操作。但想到，我們處理樹(shù)形結(jié)構(gòu)數(shù)據(jù)時(shí)，用CTE來(lái)做關(guān)系數(shù)據(jù)，做成有樹(shù)形格式的數(shù)據(jù)，如此我們也可以將這個(gè)問(wèn)題轉(zhuǎn)換成做樹(shù)形格式的問(wèn)題，代碼如下：

復(fù)制代碼代碼如下:

 
;WITH EmployeT AS( 
--員工的基本信息(使用OUTER APPLY將多個(gè)ID拆分開(kāi)來(lái),然后與部門表相關(guān)聯(lián)) 
--此時(shí)已將員工表所存的IDS分別與部門相關(guān)聯(lián),下面需要將此集合中的deptName聚合成一個(gè)記錄 
SELECT E.*,ISNULL(D.name,'') AS deptName 
FROM Employee AS E 
OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID 
LEFT JOIN Department AS D ON DID.ID=D.id 
),mike AS( 
SELECT id,name,deptIds,deptName 
,ROW_NUMBER()OVER(PARTITION BY id ORDER BY id) AS level_num 
FROM EmployeT 
),mike2 AS( 
SELECT id,name,deptIds,CAST(deptName AS NVARCHAR(100)) AS deptName,level_num 
FROM mike 
WHERE level_num=1 
UNION ALL 
SELECT m.id,m.name,m.deptIds,CAST(m2.deptName+','+m.deptName AS NVARCHAR(100)) AS deptName,m.level_num 
FROM mike AS m 
INNER JOIN mike2 AS m2 ON m.ID=m2.id AND m.level_num=m2.level_num+1 
),maxMikeByIDT AS( 
SELECT id,MAX(level_num) AS level_num 
FROM mike2 
GROUP BY ID 
) 

SELECT A.id,A.name,A.deptIds,A.deptName 
FROM mike2 AS A 
INNER JOIN maxMikeByIDT AS B ON A.id=B.ID AND A.level_num=B.level_num 
ORDER BY A.id OPTION (MAXRECURSION 0) 

結(jié)果如下：

全部SQL：

復(fù)制代碼代碼如下:

 
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Department]')) 
DROP TABLE [dbo].Department 
GO 
--部門表 
CREATE TABLE Department 
( 
id int, 
name nvarchar(50) 
) 
INSERT INTO Department(id,name) 
SELECT 1,'人事部' 
UNION 
SELECT 2,'工程部' 
UNION 
SELECT 3,'管理部' 

SELECT * FROM Department 


IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[Employee]')) 
DROP TABLE [dbo].Employee 
GO 
--員工表 
CREATE TABLE Employee 
( 
id int, 
name nvarchar(20), 
deptIds varchar(1000) 
) 
INSERT INTO Employee(id,name,deptIds) 
SELECT 1,'蔣大華','1,2,3' 
UNION 
SELECT 2,'小明','1' 
UNION 
SELECT 3,'小華','' 

SELECT * FROM Employee 

--創(chuàng)建一個(gè)表值函數(shù)，用來(lái)拆分用逗號(hào)分割的數(shù)字串，返回只有一列數(shù)字的表 
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[fun_SplitIds]')) 
DROP FUNCTION [dbo].fun_SplitIds 
GO 
CREATE FUNCTION dbo.fun_SplitIds( 
@Ids nvarchar(1000) 
) 
RETURNS @t_id TABLE (id VARCHAR(36)) 
AS 
BEGIN 
DECLARE @i INT,@j INT,@l INT,@v VARCHAR(36); 
SET @i = 0; 
SET @j = 0; 
SET @l = len(@Ids); 
while(@j < @l) 
begin 
SET @j = charindex(',',@Ids,@i+1); 
IF(@j = 0) set @j = @l+1; 
SET @v = cast(SUBSTRING(@Ids,@i+1,@j-@i-1) as VARCHAR(36)); 
INSERT INTO @t_id VALUES(@v) 
SET @i = @j; 
END 
RETURN; 
END 
GO 


;WITH EmployeT AS( 
--員工的基本信息(使用OUTER APPLY將多個(gè)ID拆分開(kāi)來(lái),然后與部門表相關(guān)聯(lián)) 
--此時(shí)已將員工表所存的IDS分別與部門相關(guān)聯(lián),下面需要將此集合中的deptName聚合成一個(gè)記錄 
SELECT E.*,ISNULL(D.name,'') AS deptName 
FROM Employee AS E 
OUTER APPLY dbo.fun_SplitIds(E.deptIds) AS DID 
LEFT JOIN Department AS D ON DID.ID=D.id 
),mike AS( 
SELECT id,name,deptIds,deptName 
,ROW_NUMBER()OVER(PARTITION BY id ORDER BY id) AS level_num 
FROM EmployeT 
),mike2 AS( 
SELECT id,name,deptIds,CAST(deptName AS NVARCHAR(100)) AS deptName,level_num 
FROM mike 
WHERE level_num=1 
UNION ALL 
SELECT m.id,m.name,m.deptIds,CAST(m2.deptName+','+m.deptName AS NVARCHAR(100)) AS deptName,m.level_num 
FROM mike AS m 
INNER JOIN mike2 AS m2 ON m.ID=m2.id AND m.level_num=m2.level_num+1 
),maxMikeByIDT AS( 
SELECT id,MAX(level_num) AS level_num 
FROM mike2 
GROUP BY ID 
) 

SELECT A.id,A.name,A.deptIds,A.deptName 
FROM mike2 AS A 
INNER JOIN maxMikeByIDT AS B ON A.id=B.ID AND A.level_num=B.level_num 
ORDER BY A.id OPTION (MAXRECURSION 0) 