list1 = [0, 2, 3,  4, 5]
 for i in list1:
     print(i,end="")     # 02345

list1 = []
list2 = [0, 1, 0, 1, 1, 1]
for i in list2:
	list1.append(str(i))
print(list1)  #  ['0', '1', '0', '1', '1', '1']
可以簡寫為：
list2 = [0, 1, 0, 1, 1, 1]
list1 = [ str(i) for i in list2 ]
print(list1)   #  ['0', '1', '0', '1', '1', '1']

num = 123456
list1 = list(str(num))
print(list1)  # ['1', '2', '3', '4', '5', '6']

list1 = ['1', '2', '3', '4', '5', '6']
list2 = []
   for i in list1:
   	list2.append(int(i))
   print(list2)  # [1, 2, 3, 4, 5, 6]

可以簡寫為
list1 = ['1', '2', '3', '4', '5', '6']
list2 = [ int(x) for x in list1 ]
print(list2)  # [1, 2, 3, 4, 5, 6]

d1 = {'name': 'revotu', 'age': 99}
d2 = {'age': 24, 'sex': 'male'}

d2.update(d1)    >> d2 = {'name': 'revotu', 'age': 24, 'sex': 'male'}
{**d1, **d2}     >>  {'name': 'revotu', 'age': 24, 'sex': 'male'} 不改變d1和d2，重新輸出一個新的字典
# 字典排序
d3 = d3 = {"a": 1, "b": 10, "c": 2}    # x[1] 表示value排序  x[0]表示按照key排序
dict(sorted(d3.items(), key=lambda x:x[1]))   >>> {'a': 1, 'c': 2, 'b': 10}

# 數(shù)字list轉(zhuǎn)換為逗號分隔的字符串
num_list = [1, 2, 3, 4, 5]
s = ','.join(map(str, num_list))
print(s)

# 逗號分隔的字符串轉(zhuǎn)換為數(shù)字list
a = "1, 2, 3, 4, 5"
c = [int(i) for i in a.split(",")]
print(c)