//關(guān)于strlen返回值的一個(gè)易錯(cuò)點(diǎn)
int main()
{
	const char* str1 = "abcdef";
	const char* str2 = "bbb";
	if (strlen(str2) - strlen(str1) > 0)
	{
		printf("str2>str1\n");
	}
	else
	{
		printf("srt1>str2\n");
	}
	return 0;
}

size_t my_strlen1(const char* str)
{
	assert(str);
	int count = 0;
	while (*str++)
	{
		count++;
	}
	return count;
}

size_t my_strlen2(const char* str)
{
	assert(str);
	char* start = str;
	while (*str!='\0')//注意這種寫(xiě)法不能寫(xiě)*str++;這里要先判斷再++；*str++的寫(xiě)法在'\0'的地方也+1了
	{
		str++;
	}
	return str - start;//\0與起始位置的差就是字符數(shù)
}

size_t my_strlen3(const char* str)
{
	if ('\0' == *str)
		return 0;
	else
		return 1 + my_strlen3(str + 1);
}

char* my_strcpy(char* dest, const char* src)
{
	assert(dest && src);
	char* ret = dest;
	while (*dest++ = *src++)
	{
		;
	}
	return ret;
}
int main()
{
	char arr1[20] = "hello underworld";//注意寫(xiě)成數(shù)組
	char arr2[20] = "hello world";

	printf("%s\n", arr2);
	printf("%s\n", my_strcpy(arr2, arr1));

	return 0;
}

char* my_strcat(char* dest, const char* src)
{
	char* ret = dest;
	assert(dest && src);
	while (*dest)//讓dest到達(dá)str1的\0位置
	{
		dest++;
	}
	while (*dest++ = *src++)//這一部分和strcpy同
	{
		;
	}
	return ret;
}
int main()
{
	char arr1[20] = "hello ";
	char arr2[20] = "underworld";

	printf("%s\n", my_strcat(arr1, arr2));

	return 0;
}

int my_strcmp(const char* str1, const char* str2)
{
	while (*str1 == *str2)
	{
		if (*str1 == '\0')//說(shuō)明兩個(gè)字符串同時(shí)到達(dá)結(jié)束標(biāo)記
			return 0;
		str1++;
		str2++;
	}
	return *str1 - *str2;//如果不是在循環(huán)內(nèi)部返回，就一定不相等，而字符相減可以反映大小
}
int main()
{
	char *str1 = "hello world";
	char *str2 = "hello underworld";

	printf("%d\n", my_strcmp(str1, str2));//w比u大

	return 0;
}

char* my_strstr(const char* str1, const char* str2)
{
	assert(str1 && str2);

	char* s1;//s1維護(hù)str1
	char* s2;//s2維護(hù)str2
	char* cp = str1;//cp用來(lái)記錄比較開(kāi)始的位置

	if (*str2 == '\0')//特殊情況
		return str1;

	while (*cp)
	{
		s1 = cp;
		s2 = str2;

		while (*s1 != '\0' && *s2 != '\0' && *s1 == *s2)//其實(shí)*s1='\0'且*s2!='\0'時(shí)已經(jīng)沒(méi)有比較下去的必要了
			//*s1==*s2就讓兩個(gè)維護(hù)指針?lè)謩e+1；不等就讓cp+1,s1和s2分別重置		
		{
			s1++;
			s2++;
		}
		if (*s2 == '\0')//*s2=='\0'說(shuō)明找到了
		{
			return cp;
		}
		cp++;
	}

	return NULL;
}

void get_next(char* str, int* next)
{
	int i, k;
	i = 0;
	k = -1;
	next[0] = -1;//這個(gè)值沒(méi)用；或者說(shuō)是為了使i增加而j不增加
	int len = strlen(str);
	while (i < len - 1)//next數(shù)組最大下標(biāo)是字符串長(zhǎng)度減1，數(shù)組長(zhǎng)度和字符串長(zhǎng)度相同
	{
		if (k == -1 || *(str + i) == *(str + k))
		{
			++i;
			++k;
			next[i] = k;
		}
		else
			k = next[k];
	}

	//測(cè)試打印next
	int z;
	printf("next:");
	for (z = 0; z < len; z++)
	{
		printf("%d ", next[z]);
	}
	printf("\n");
}

int Index_KMP(char* str1, char* str2, int pos)
{
	int i = pos;
	int j = 0;
	int next[255];
	get_next(str2, next);
	int len1 = strlen(str1);
	int len2 = strlen(str2);
	int count = 0;
	while (i < len1 && j < len2)//i從0到10(len1=11)，共11次，但是考慮到走else的回溯，單字符查找一共循環(huán)22次
	{
		count++;
		if (j == -1 || *(str1 + i) == *(str2 + j))//先判斷，再把下標(biāo)加1
		{
			++i;
			++j;
		}
		else
		{
			j = next[j];
		}
	}
	printf("i=%d\n", i);
	printf("j=%d\n", j);
	printf("count=%d\n", count);//是存在回溯的，那么這個(gè)函數(shù)的時(shí)間復(fù)雜度還是O(m)嗎？
	//if ((len2!=1) && (j >=(len2-1)))//有缺陷，對(duì)于len2=1的情況無(wú)法處理
	if (j >= (len2 - 1))//單字符查找情形，while結(jié)束時(shí)j=0，而len2-1也=0，故不能作為找到了的標(biāo)志
		//對(duì)于單字符查找以外的情形，len2-1一定大于0，len2-1代表的就是目標(biāo)串最后一個(gè)字符的下標(biāo)，既然j
		//到達(dá)了這個(gè)位置，就說(shuō)明完全匹配了
		return i - len2;//由于字符串長(zhǎng)度與數(shù)組下標(biāo)的差異造成len2=1時(shí)
	else
		return 0;
}
int main()
{
	char* str1 = "hello underworld!";
	char* str2 = "under";

	printf("%s\n", my_strstr(str1, str2));
	printf("%s\n", *(str1+Index_KMP(str1, str2, 0)));

	return 0;
}

int main()
{
	char arr1[20] = "abcdefghi";
	char arr2[] = "xxxx";

	//strncpy(arr1, arr2, 6);//從arr2拷貝6個(gè)字符給arr1?如果arr2長(zhǎng)度不夠，則補(bǔ)0
	//strncpy(arr1, arr2, 3);//長(zhǎng)度不夠不拷貝\0
	//strncpy(arr1, arr2, 4);
	strncpy(arr1, arr2, 5);

	printf("%s\n", arr1);
	return 0;
}

int main()
{
	char arr1[20] = "abc\0xxxxxxx";
	char arr2[] = "def";

	//strncat(arr1, arr2, 6);//在arr1后面接上arr2的六個(gè)字符？最多只接arr2這么長(zhǎng)的字符串，包括\0
	//strncat(arr1, arr2, 3);//自己會(huì)加上\0
	strncat(arr1, arr2, 2);

	printf("%s\n", arr1);
	return 0;
}

int main()
{
	char arr1[] = "abcdew";
	char arr2[] = "abcdeqj";

	printf("%d\n",strncmp(arr1, arr2, 5));
	printf("%d\n",strncmp(arr1, arr2, 6));

	return 0;
}

int main()
{
	char arr1[] = "cjh@scu.edu";
	char arr2[100] = { 0 };//保存臨時(shí)數(shù)據(jù)
	char sep[] = "@.";
	char* ret = NULL;//接收strtok的返回值
	strcpy(arr2, arr1);
	for (ret = strtok(arr2, sep); ret != NULL; ret = strtok(NULL, sep))
	{
		printf("%s\n", ret);
	}

	return 0;
}

int main()
{
	char str[] = "- This, a sample string.";
	char* pch;
	printf("Splitting string \"%s\" into tokens:\n", str);
	pch = strtok(str, ", .-");//分隔標(biāo)記的位置不重要
	while (pch != NULL)
	{
		printf("%s\n", pch);
		pch = strtok(NULL, " ,.-");//注意這里有空格
	}
	return 0;
}

void* my_memcpy(void* dest, void* src, size_t count)
{
	void* ret = dest;
	assert(dest && src);

	while (count--)
	{
		*(char*)dest = *(char*)src;
		dest = (char*)dest + 1;
		src = (char*)src + 1;
	}
	//printf("%d\n", count);//count=-1
	return ret;
}
int main()
{
	int arr1[10] = { 1,2,3,4,5,6,7,8,9,10 };
	int arr2[20] = { 0 };

	my_memcpy(arr2, arr1, 10 * sizeof(int));

	int i;
	for (i = 0; i < 20; i++)
	{
		printf("%d ", arr2[i]);
	}

	return 0;

#include <stdio.h>
#include <string.h>
int main()
{
	char str[] = "memmove can be very useful......";
	printf("%c\n", *(str + 15));
	printf("%c\n", *(str + 20));

	memmove(str + 20, str + 15, 11);//注意memmove和memcpy不會(huì)遇到\0停下來(lái)，什么時(shí)候停取決于第三個(gè)參數(shù)
	puts(str);
	return 0;
}

void* my_memmove(void* dest, void* src, size_t count)//關(guān)鍵在于拷貝之前先判斷是否會(huì)出現(xiàn)overlap
{
	void* ret = dest;
	if (dest <= src || (char*)dest >= ((char*)src + count))
	{
		while (count--)
		{
			*(char*)dest = *(char*)src;
			dest = (char*)dest + 1;
			src = (char*)src + 1;
		}
	}
	else
	{
		dest = (char*)dest + count - 1;
		src = (char*)src + count - 1;
		while (count--)
		{
			*(char*)dest = *(char*)src;
			dest = (char*)dest - 1;
			src = (char*)src - 1;
		}
	}
	return ret;
}
int main()
{
	int arr[10] = { 1,2,3,4,5,6,7,8,9,10 };

	my_memmove(arr + 2, arr, 4 * sizeof(int));//1 2 1 2 3 4 7 8 9 10  
	//my_memcpy(arr + 2, arr, 4 * sizeof(int));//1 2 1 2 1 2 7 8 9 10

	int i;
	for (i = 0; i < 10; i++)
	{
		printf("%d ", arr[i]);
	}
	return 0;
}

#include <stdio.h>
#include <string.h>
int main()
{
	char buffer1[] = "DWgaOtP12df0";
	char buffer2[] = "DWGAOTP12DF0";
	int n;
	n = memcmp(buffer1, buffer2, sizeof(buffer1));
	if (n > 0) printf("'%s' is greater than '%s'.\n", buffer1, buffer2);
	else if (n < 0) printf("'%s' is less than '%s'.\n", buffer1, buffer2);
	else printf("'%s' is the same as '%s'.\n", buffer1, buffer2);
	return 0;
}

#include <stdio.h>
int main ()
{
  int i=0;
  char str[]="Test String.\n";
  char c;
  while (str[i])
 {
    c=str[i];
    if (isupper(c)) 
        c=tolower(c);
    putchar (c);
    i++;
 }
  return 0; }