<S extends T> S save(S entity);
<S extends T> Iterable<S> saveAll(Iterable<S> entities);
Optional<T> findById(ID id);
boolean existsById(ID id);
Iterable<T> findAll();
Iterable<T> findAllById(Iterable<ID> ids);
long count();
void deleteById(ID id);
void delete(T entity);
void deleteAll(Iterable<? extends T> entities);
void deleteAll();

/**
 * Returns a reference to the entity with the given identifier. Depending on how the JPA persistence provider is
 * implemented this is very likely to always return an instance and throw an
 * {@link javax.persistence.EntityNotFoundException} on first access. Some of them will reject invalid identifiers
 * immediately.
 *
 * @param id must not be {@literal null}.
 * @return a reference to the entity with the given identifier.
 * @see EntityManager#getReference(Class, Object) for details on when an exception is thrown.
 */
T getOne(ID id);

public T getOne(ID id) {
    Assert.notNull(id, "The given id must not be null!");
    return this.em.getReference(this.getDomainClass(), id);
}

public Optional<T> findById(ID id) {
    Assert.notNull(id, "The given id must not be null!");
    Class<T> domainType = this.getDomainClass();
    if (this.metadata == null) {
        return Optional.ofNullable(this.em.find(domainType, id));
    } else {
        LockModeType type = this.metadata.getLockModeType();
        Map<String, Object> hints = this.getQueryHints().withFetchGraphs(this.em).asMap();
        return Optional.ofNullable(type == null ? this.em.find(domainType, id, hints) : this.em.find(domainType, id, type, hints));
    }
}

Foo foo = repository.findById(id)
                    .orElse(null);
Foo foo = repository.findById(id)
                    .orElse(new Object());