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python實現(xiàn)雙人五子棋（終端版）

更新時間：2020年12月30日 14:23:47 作者：Miku丨無形

這篇文章主要為大家詳細介紹了python實現(xiàn)終端版的雙人五子棋，文中示例代碼介紹的非常詳細，具有一定的參考價值，感興趣的小伙伴們可以參考一下

五子棋還是有很多大佬發(fā)的，今天我也發(fā)一篇萌新寫的小五子棋，這個是終端版的，如果有問題請大家指出，我去修改

代碼如下：

screen = []
screen_change=0

def into():#初始空白棋盤
 for i in range(screen_change):
 list_width=[]
 for j in range(screen_change):
 list_width.append(' '+' |')
 screen.append(list_width)

def user_black():
 while True:
 coordinate = input("黑方請輸入你想填下子的坐標 例1,2或者5,5")
 coordinate=coordinate.split(',')
 width_num = int(coordinate[0]) - 1
 high_num = int(coordinate[1]) - 1
 if screen[width_num][high_num][1]!=' ':
 print('你輸入的地方已經(jīng)有棋子了，請重新輸入')
 continue
 screen[width_num][high_num] = ' ' + '@' + ' |'
 break
 screen_print()

def user_white():
 while True:
 coordinate = input("白方請輸入你想填下子的坐標 例1,2或者5,5")
 coordinate = coordinate.split(',')
 width_num = int(coordinate[0]) - 1
 high_num = int(coordinate[1]) - 1
 if screen[width_num][high_num][1] != ' ':
 print('你輸入的地方已經(jīng)有棋子了，請重新輸入')
 continue
 screen[width_num][high_num] = ' ' + '#' + ' |'
 break
 screen_print()

def eeferee():#判斷輸贏
 #判斷行
 for i in range(screen_change):
 for j in range(screen_change-4):
 if screen[i][j][1]==screen[i][j+1][1]==screen[i][j+2][1]==screen[i][j+3][1]==screen[i][j+4][1] and screen[i][j][1]!=' ':
 return False
 for i in range(screen_change - 4):
 for j in range(screen_change):
 if screen[i][j][1]==screen[i+1][j][1]==screen[i+2][j][1]==screen[i+3][j][1]==screen[i+4][j][1] and screen[i][j][1]!=' ':
 return False
 for i in range(screen_change - 4):
 for j in range(screen_change - 4):
 if screen[i][j][1]==screen[i+1][j+1][1]==screen[i+2][j+2][1]==screen[i+3][j+3][1]==screen[i+4][j+4][1] and screen[i][j][1]!=' ':
 return False
 for k in range(4,screen_change):
 if k>=4:
 if screen[i][k][1] == screen[i+1][k-1][1] == screen[i+2][k-2][1] == screen[i+3][k-3][1] == screen[i+4][k-4][1] and screen[i][k][1] != ' ':
  return False
 return True

def screen_print():#打印棋盤
 print('——' * (screen_change*3+1))
 for i in range(screen_change):
 print('|',end=' ')
 for j in range(screen_change):
 print(screen[i][j],end=' ')
 print()
 print('——'*(screen_change*3+1))

def main():
 global screen_change
 screen_change = int(input('請輸入你設(shè)定的棋盤大小：'))
 into()
 screen_print()
 while eeferee():
 user_black()
 if not eeferee():
 break
 user_white()
 print('游戲結(jié)束')

if __name__=='__main__':
 main()

效果圖如下：