python實現(xiàn)人性化顯示金額數(shù)字實例詳解
我們在開發(fā)過程中,有時候需要把float,int型等數(shù)字作為金額類型數(shù)字顯示會出現(xiàn)很多問題,比如float會顯示成 965868.4599999,int型沒有小數(shù)位等各種各樣的問題。我們需要進行轉換顯示,才能保證閱讀人性化。
方法一:
這里只貼上主要代碼:
# 金額人性化
def humanized_amount(self, *args, **kwargs):
"""
金額人性化,保留二位小數(shù),再進行人性化顯示
compel強制二位,默認True,
"""
if not CheckData(self.__mark).is_int_or_float:
return {"code": "0001", "msg": "必須傳入數(shù)字", "data": None}
else:
figure = float(self.__mark)
# 保留二位小數(shù)
figure = "{:.2f}".format(figure)
# 人性化顯示
figure = "{:,}".format(float(figure))
if kwargs.get("compel", True):
# 進行處理,保留二位小數(shù),如果不足二位補領
figure_list = figure.split(".")
if len(figure_list[1]) == 1:
figure += "0"
return figure
方法二:利用xToolkit庫
安裝方法:
pip install xToolkit -i http://pypi.douban.com/simple --trusted-host pypi.douban.com
xToolkit庫是我自己封裝的python內置庫的一個擴展庫.把python的datetime,string,list,dist,xthread等數(shù)據(jù)結構進行了功能的擴展。
使用方法比較簡單,一行代碼即可搞定
# 金額人性化,保留二位小數(shù)
xstring.dispose(3.0).humanized_amount(compel=False)
xstring.dispose("3.0").humanized_amount(compel=True)
xstring.dispose(37787841.902).humanized_amount(compel=False)
xstring.dispose("37787841.902").humanized_amount(compel=True)
xstring.dispose(378978989).humanized_amount(compel=False)
xstring.dispose("378978989").humanized_amount(compel=True)
>>3.0
>>3.00
>>37,787,841.9
>>37,787,841.90
>>378,978,989.0
>>378,978,989.00
實例擴展:
用python實現(xiàn)把數(shù)字人民幣金額轉換成大寫的腳本程序
# -*- coding: utf-8 -*-
def Num2MoneyFormat( change_number ):
"""
.轉換數(shù)字為大寫貨幣格式( format_word.__len__() - 3 + 2位小數(shù) )
change_number 支持 float, int, long, string
"""
format_word = ["分", "角", "元",
"拾","百","千","萬",
"拾","百","千","億",
"拾","百","千","萬",
"拾","百","千","兆"]
format_num = ["零","壹","貳","叁","肆","伍","陸","柒","捌","玖"]
if type( change_number ) == str:
# - 如果是字符串,先嘗試轉換成float或int.
if '.' in change_number:
try: change_number = float( change_number )
except: raise ValueError, '%s can\'t change'%change_number
else:
try: change_number = int( change_number )
except: raise ValueError, '%s can\'t change'%change_number
if type( change_number ) == float:
real_numbers = []
for i in range( len( format_word ) - 3, -3, -1 ):
if change_number >= 10 ** i or i < 1:
real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) )
elif isinstance( change_number, (int, long) ):
real_numbers = [ int( i ) for i in str( change_number ) + '00' ]
else:
raise ValueError, '%s can\'t change'%change_number
zflag = 0 #標記連續(xù)0次數(shù),以刪除萬字,或適時插入零字
start = len(real_numbers) - 3
change_words = []
for i in range(start, -3, -1): #使i對應實際位數(shù),負數(shù)為角分
if 0 <> real_numbers[start-i] or len(change_words) == 0:
if zflag:
change_words.append(format_num[0])
zflag = 0
change_words.append( format_num[ real_numbers[ start - i ] ] )
change_words.append(format_word[i+2])
elif 0 == i or (0 == i%4 and zflag < 3): #控制 萬/元
change_words.append(format_word[i+2])
zflag = 0
else:
zflag += 1
if change_words[-1] not in ( format_word[0], format_word[1]):
# - 最后兩位非"角,分"則補"整"
change_words.append("整")
return ''.join(change_words)
print Num2MoneyFormat( 343.45 )
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