a=[1,2,3]
b=[4,5,6]
c=[7,8,9,10]  

#兩個list去zip()
zip(a,b)

#三個list去zip(),返回的對象的長度和最小的迭代器一致
zip(a,b,c)

#用list()查看zip后的數(shù)據(jù)
list(zip(a,b)) #[(1, 4), (2, 5), (3, 6)]
list(zip(a,b,c)) #[(1, 4, 7), (2, 5, 8), (3, 6, 9)]

#使用zip(*zip())解壓
a1,b1=zip(*zip(a,b))

#兩個list迭代輸出
for i,j in zip(a,b):
  print(i,j)
  

#將zip對象轉(zhuǎn)換成字典看看
a=[1,2,3]
d=[['a','b','c'],['aa','bb','cc'],['aaa','bbb','ccc']]

dict(zip(a,d)) #{1: ['a', 'b', 'c'], 2: ['aa', 'bb', 'cc'], 3: ['aaa', 'bbb', 'ccc']}
#如果一個是key值，一個內(nèi)層list就是一行value
[dict(zip(a,value)) for value in d] #[{1: 'a', 2: 'b', 3: 'c'},
 {1: 'aa', 2: 'bb', 3: 'cc'},
 {1: 'aaa', 2: 'bbb', 3: 'ccc'}]

#或者是  
l=[]
for value in d:
  dict={}
  for i in range(len(value)):
    dict[a[i]]=value[i]
  l.append(dict)

dict_1=dict(zip(a,b)) #{1: 4, 2: 5, 3: 6}
dict_2=dict(zip(a,d)) # {1: ['a', 'b', 'c'], 2: ['aa', 'bb', 'cc'], 3: ['aaa', 'bbb', 'ccc']}


#key的遍歷
for i,j in zip(dict_1,dict_2):
  print(i,j)

#values的遍歷
for i ,j in zip(dict_1.values(),dict_2.values()):
  print(i,j)

#同時遍歷,需要2個dict的value都是多層的
dict_4=dict(zip(b,d))  #{4: ['a', 'b', 'c'], 5: ['aa', 'bb', 'cc'], 6: ['aaa', 'bbb', 'ccc']}
for i,j in zip(dict_4,dict_2):
  for k in dict_4[i]:
    print(i,k)
  for m in dict_2[j]:
    print(j,m)