#!/user/bin/python
# -*- coding: utf-8 -*-
import os
import sys
#棋盤(pán)模塊
def model(dictionary,serial=False):
 if serial:
  print('-(初版)井字棋游戲,輸入棋號(hào)進(jìn)行對(duì)戰(zhàn),')
  print('對(duì)應(yīng)棋號(hào)為第一行:a1-a2-a3',end=',')
  print('對(duì)應(yīng)棋號(hào)為第二行:b1-b2-b3',end=',')
  print('對(duì)應(yīng)棋號(hào)為第三行:c1-c2-c3')
 print(dictionary['a1'] + ' | '+ dictionary['a2'] +' | '+ dictionary['a3'] +' | ')
 print('- +- +- +-')
 print(dictionary['b1'] + ' | ' + dictionary['b2'] + ' | ' + dictionary['b3'] + ' | ')
 print('- +- +- +-')
 print(dictionary['c1'] + ' | ' + dictionary['c2'] + ' | ' + dictionary['c3'] + ' | ')
#主模塊
def main():
 dictionary={'a1':' ','a2':' ','a3':' ','b1':' ','b2':' ','b3':' ','c1':' ','c2':' ','c3':' '}
 model(dictionary, True)
 u1 = 'x' #用戶(hù)1
 u2 = 'o' #用戶(hù)2
 stepNumber =1 #記錄步數(shù)
 break_fang = 0 #獲勝者記錄
 while(stepNumber<=9):
 fv = True # 判斷條件2
 while fv:
  num = input('請(qǐng)用戶(hù)u1開(kāi)始下棋:')
  compare=1 #判斷條件1
  for x in dictionary:
  if x.find(num)!=-1:compare=0
  if compare ==0:
  fv=False
 dictionary[num] = u1
 model(dictionary)
 # 0:繼續(xù) 1,用戶(hù)1勝,2,用戶(hù)2勝
 break_fang = forResult(dictionary)
 if break_fang > 0: break
 fv =True #清楚狀態(tài)
 stepNumber+=1
 while fv:
  num1=input('請(qǐng)用戶(hù)u2開(kāi)始下棋:')
  compare = 1 # 判斷條件1
  for x in dictionary:
  if x.find(num1)!=-1:compare=0
  if compare == 0:
  fv=False
 dictionary[num1] = u2
 model(dictionary)
 break_fang = forResult(dictionary)
 if break_fang > 0: break
 stepNumber+=1
 gameover(break_fang)
#退出下棋
def gameover(break_fang):
 c = input('是否重新開(kāi)始? yes:no:')
 if c.find('yes')!=-1:
 main()
 else:
 print('-游戲結(jié)束-')
 return
#判斷獲勝情況
#dictionary:棋盤(pán)信息
def forResult(dictionary):
 dicts= dict(dictionary)
 if dicts['a1'] == dicts['a2'] and dicts['a2'] == dicts['a3'] and len(dicts['a3'].strip())>0:
 print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['a1'] == 'x' else '用戶(hù)2-獲勝')
 return 1 if dicts['a1']=='x' else 2
 elif dicts['a1'] == dicts['b2'] and dicts['b2'] == dicts['c3'] and len(dicts['c3'].strip())>0:
 print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['a1'] == 'x' else '用戶(hù)2-獲勝')
 return 1 if dicts['a1'] == 'x' else 2
 elif dicts['a1'] == dicts['b1'] and dicts['b1'] == dicts['c1'] and len(dicts['c1'].strip())>0:
  print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['a1'] == 'x' else '用戶(hù)2-獲勝')
  return 1 if dicts['a1'] == 'x' else 2
 elif dicts['a2'] == dicts['b2'] and dicts['b2'] == dicts['c2'] and len(dicts['c2'].strip())>0:
 print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['a2'] == 'x' else '用戶(hù)2-獲勝')
 return 1 if dicts['a2'] == 'x' else 2
 elif dicts['a3'] == dicts['b3'] and dicts['b3'] == dicts['c3'] and len(dicts['c3'].strip())>0:
  print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['a3'] == 'x' else '用戶(hù)2-獲勝')
  return 1 if dicts['a3'] == 'x' else 2
 elif dicts['a3'] == dicts['b2'] and dicts['b3'] == dicts['c1'] and len(dicts['c1'].strip())>0:
  print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['a3'] == 'x' else '用戶(hù)2-獲勝')
  return 1 if dicts['a3'] == 'x' else 2
 elif dicts['b1'] == dicts['b2'] and dicts['b2'] == dicts['b3'] and len(dicts['b3'].strip())>0:
  print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['b1'] == 'x' else '用戶(hù)2-獲勝')
  return 1 if dicts['b1'] == 'x' else 2
 elif dicts['c1'] == dicts['c2'] and dicts['c2'] == dicts['c3'] and len(dicts['c3'].strip())>0:
  print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dicts['c1'] == 'x' else '用戶(hù)2-獲勝')
  return 1 if dicts['c1'] == 'x' else 2
 else:
 return 0
if __name__ =='__main__':
 main()

def compares(dictionary={'':''},string=''):
 if len(dictionary)>0 | len(string.strip())==0:print('傳值為空!')
 else:
 axle =('a1','a3','b2','c1','c3') # 四個(gè)角和中間的數(shù)特殊判斷 條件1
 axle_fang=False #特殊棋號(hào)需要多加一種可能性
 for x in axle:
  if string==x:axle_fang=True
 if axle_fang: #條件1
  if dictionary['a1']==dictionary['b2'] and dictionary['b2']==dictionary['c3'] and dictionary['c3'].strip()!=''\
   or dictionary['a3']==dictionary['b2'] and dictionary['b2']==dictionary['c1']and dictionary['c1'].strip()!='':
   print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dictionary[string] == 'x' else '用戶(hù)2-獲勝')
   return 1 if dictionary[string] == 'x' else 2
 # 拆分棋號(hào) splitStr0,splitStr1,普通棋號(hào)只需判斷倆種a倆種可能,上下-左右間的位置
 splitStr0,splitStr1 = string[0],string[1]
 print(splitStr0+":"+splitStr1)
 if dictionary[splitStr0+'1']==dictionary[splitStr0+'2'] and dictionary[splitStr0+'2']==dictionary[splitStr0+'3']\
  or dictionary['a'+splitStr1]==dictionary['b'+splitStr1] and dictionary['b'+splitStr1]==dictionary['c'+splitStr1]:
  print('游戲結(jié)束,' + '用戶(hù)1-獲勝' if dictionary[string] == 'x' else '用戶(hù)2-獲勝')
  return 1 if dictionary[string] == 'x' else 2
 else:return 0