shell打印給定日期的日歷

更新時間：2019年07月31日 12:02:27 作者：小他529

這篇文章主要為大家詳細介紹了shell打印給定日期的日歷，具有一定的參考價值，感興趣的小伙伴們可以參考一下

學習shell有一段時間了，一直沒有機會練手，看到同事發(fā)了一張照片，控制臺顯示了當月的日歷，是用Python實現(xiàn)的，感覺挺好玩，所以準備用shell來實現(xiàn)一個，搞了一下午，終于搞定。

打印本月的日期

#! /bin/bash
#設置字體顏色
tiffcolor="\033[0;35m"
menucolor="\033[0;33m"
todaycolor="\033[0;35;44m"
start="\033[0m"

#計算各個日期
month=`date +%m`
day=`date +%d`
year=`date +%Y`
weekday=`date -d "$year-$month-01" +%w`
nextmonth=`expr $month + 1`
today=`date +%d`
#計算本月有多少天
differ=$(( ($(date -d "$year-$nextmonth-01" +%s) - $(date +%s))/(24*60*60) )) 
days=`expr $differ + $day`

#打印標題
echo -en "${menucolor}"
echo -en "\t  $year $month\n"
echo "SUN MON TUE WEN THU FRI SAT"
echo -en "${start}"

#打印空格
if [ $weekday -ne 0 ];then
for((i=1;i<=$weekday;i++))
do
  echo -n "  "
  echo -n " "
done
fi

#打印日期
for((i=1;i<=$days;i++))
do
  printf "%s" " "
  echo -en "${tiffcolor}"
  #今天高亮顯示
    if [ $today -eq $i ];then
      echo -en "${todaycolor}"
    fi
  printf "%2d" $i
  echo -en "${start}"
  echo -en " "
  if [ $((($weekday+$i)%7)) == 0 ];then
    echo ""
  fi
#  printf "%3d " $i
done
echo ""

執(zhí)行結果：

擴展：給定任意日期，打印當月的日期

#! /bin/bash
#date=$1
tiffcolor="\033[0;35m"
menucolor="\033[0;33m"
todaycolor="\033[0;35;44m"
start="\033[0m"


if [ $# -ne 1 ];then
  echo "plz input the date"
  exit 1
fi
date=$1
count=`echo $date |grep -o '-'|wc -l`
if [ $count -ne 2 ];then
  echo "plz input correct date"
  exit 1
fi
year=`echo $date|cut -d "-" -f 1`
month=`echo $date|cut -d "-" -f 2`
day=`echo $date|cut -d "-" -f 3`
expr $year + $month + $day + 0 &>/dev/null
if [ $? -ne 0 ];then
  echo "plz input a correct date"
  exit 1
elif [ $month -gt 12 -o $month -eq 0 ];then
  echo "plz input the month between 1 and 12"
  exit 1
elif [ $day -gt 31 -o $day -eq 0 ];then
  echo "plz input the day between 1 and 31"
  exit 1
fi

#nextmonth=$(( $month + 1))
#month=`date -d "$date" +%m`
#day=`date -d "$date" +%d`
#year=`date -d "$date" +%Y`
weekday=`date -d "$year-$month-01" +%w`
if [ $month -eq 12 ];then
  newmonth=1
  newyear=`expr $year + 1`
else
  newyear=$year
  #nextmonth= expr $month + 1
  newmonth=`expr $month + 1`
fi
days=$(( ($(date -d "${newyear}-${newmonth}-01" +%s) - $(date -d "$year-$month-01" +%s))/(24*60*60) )) 
#echo $days
echo -en "${menucolor}"
echo -en "\t  $year $month\n"
echo "SUN MON TUE WEN THU FRI SAT"
echo -en "${start}"

if [ $weekday -ne 0 ];then
for((i=1;i<=$weekday;i++))
do
  echo -n "  "
  echo -n " "
done
fi


for((i=1;i<=$days;i++))
do
  printf "%s" " "
  echo -en "${tiffcolor}"
    if [ $day -eq $i ];then
      echo -en "${todaycolor}"
    fi
  printf "%2d" $i
  echo -en "${start}"
  echo -en " "
  if [ $((($weekday+$i)%7)) == 0 ];then
    echo ""
  fi
#  printf "%3d " $i
done
echo ""

執(zhí)行結果：