js比較兩個單獨的數(shù)組或?qū)ο笫欠裣嗟鹊膶嵗a
所謂js的中的傳值,其實也就是說5種基本數(shù)據(jù)類型(null,undefind,boolean,number,string)
傳引用也就是說的那個引用數(shù)據(jù)類型,(array和object)
基本數(shù)據(jù)類型的值不可變,而引用數(shù)據(jù)類型的值是可變的
所以當(dāng)你比較數(shù)組和對象時,都是false;除非你是克隆的原份數(shù)據(jù)
即: var a = { name: "李四" }; var b = a;
大家通常稱對象為引用類型,以此來和基本類型進(jìn)行區(qū)分; 而對象值都是引用,所以的對象的比較也叫引用的比較,當(dāng)且當(dāng)他們都指向同一個引用時,即都引用的同一個基對象時,它們才相等.
1.比較兩個單獨的數(shù)組是否相等
JSON.stringify(a1) == JSON.stringify(a2)
或
a1.toString() == a2.toString()
要判斷2個數(shù)組是否相同,把數(shù)組轉(zhuǎn)換成字符串進(jìn)行比較。
如果要比較兩個數(shù)組的元素是否相等,則:
JSON.stringify([1,2,3].sort()) === JSON.stringify([3,2,1].sort());
或
[1,2,3].sort().toString() === [3,2,1].sort().toString();
判斷2個數(shù)組是否相同,首先要把數(shù)組進(jìn)行排序,然后轉(zhuǎn)換成字符串進(jìn)行比較。
2.比較兩個單獨的對象是否相等
let cmp = ( x, y ) => {
// If both x and y are null or undefined and exactly the same
if ( x === y ) {
return true;
}
// If they are not strictly equal, they both need to be Objects
if ( ! ( x instanceof Object ) || ! ( y instanceof Object ) ) {
return false;
}
//They must have the exact same prototype chain,the closest we can do is
//test the constructor.
if ( x.constructor !== y.constructor ) {
return false;
}
for ( var p in x ) {
//Inherited properties were tested using x.constructor === y.constructor
if ( x.hasOwnProperty( p ) ) {
// Allows comparing x[ p ] and y[ p ] when set to undefined
if ( ! y.hasOwnProperty( p ) ) {
return false;
}
// If they have the same strict value or identity then they are equal
if ( x[ p ] === y[ p ] ) {
continue;
}
// Numbers, Strings, Functions, Booleans must be strictly equal
if ( typeof( x[ p ] ) !== "object" ) {
return false;
}
// Objects and Arrays must be tested recursively
if ( ! Object.equals( x[ p ], y[ p ] ) ) {
return false;
}
}
}
for ( p in y ) {
// allows x[ p ] to be set to undefined
if ( y.hasOwnProperty( p ) && ! x.hasOwnProperty( p ) ) {
return false;
}
}
return true;
};
下面是StackOverflow大神封裝的方法,可以學(xué)習(xí)一下:
1.比較數(shù)組
// Warn if overriding existing method
if(Array.prototype.equals)
console.warn("Overriding existing Array.prototype.equals. Possible causes: New API defines the method, there's a framework conflict or you've got double inclusions in your code.");
// attach the .equals method to Array's prototype to call it on any array
Array.prototype.equals = function (array) {
// if the other array is a falsy value, return
if (!array)
return false;
// compare lengths - can save a lot of time
if (this.length != array.length)
return false;
for (var i = 0, l = this.length; i < l; i++) {
// Check if we have nested arrays
if (this[i] instanceof Array && array[i] instanceof Array) {
// recurse into the nested arrays
if (!this[i].equals(array[i]))
return false;
}
else if (this[i] != array[i]) {
// Warning - two different object instances will never be equal: {x:20} != {x:20}
return false;
}
}
return true;
}
// Hide method from for-in loops
Object.defineProperty(Array.prototype, "equals", {enumerable: false});
2.比較對象
Object.prototype.equals = function(object2) {
//For the first loop, we only check for types
for (propName in this) {
//Check for inherited methods and properties - like .equals itself
//https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/hasOwnProperty
//Return false if the return value is different
if (this.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) {
return false;
}
//Check instance type
else if (typeof this[propName] != typeof object2[propName]) {
//Different types => not equal
return false;
}
}
//Now a deeper check using other objects property names
for(propName in object2) {
//We must check instances anyway, there may be a property that only exists in object2
//I wonder, if remembering the checked values from the first loop would be faster or not
if (this.hasOwnProperty(propName) != object2.hasOwnProperty(propName)) {
return false;
}
else if (typeof this[propName] != typeof object2[propName]) {
return false;
}
//If the property is inherited, do not check any more (it must be equa if both objects inherit it)
if(!this.hasOwnProperty(propName))
continue;
//Now the detail check and recursion
//This returns the script back to the array comparing
/**REQUIRES Array.equals**/
if (this[propName] instanceof Array && object2[propName] instanceof Array) {
// recurse into the nested arrays
if (!this[propName].equals(object2[propName]))
return false;
}
else if (this[propName] instanceof Object && object2[propName] instanceof Object) {
// recurse into another objects
//console.log("Recursing to compare ", this[propName],"with",object2[propName], " both named \""+propName+"\"");
if (!this[propName].equals(object2[propName]))
return false;
}
//Normal value comparison for strings and numbers
else if(this[propName] != object2[propName]) {
return false;
}
}
//If everything passed, let's say YES
return true;
}
總結(jié)
以上所述是小編給大家介紹的js比較兩個單獨的數(shù)組或?qū)ο笫欠裣嗟鹊膶嵗a,希望對大家有所幫助,如果大家有任何疑問請給我留言,小編會及時回復(fù)大家的。在此也非常感謝大家對腳本之家網(wǎng)站的支持!
如果你覺得本文對你有幫助,歡迎轉(zhuǎn)載,煩請注明出處,謝謝!
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