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基于PHP RSA密文過長加密解密越過1024的解決方法

更新時(shí)間：2018年03月21日 09:11:14 作者：httpp886

下面小編就為大家分享一篇基于PHP RSA密文過長加密解密越過1024的解決方法，具有很好的參考價(jià)值，希望對大家有所幫助。一起跟隨小編過來看看吧

如下所示：

<?php
namespace helpers;

class OpensslRSA{

 //echo $private_key 私鑰;
 public $private_key = '-----BEGIN RSA PRIVATE KEY-----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-----END RSA PRIVATE KEY-----';

 //公鑰
 public $public_key = '-----BEGIN PUBLIC KEY-----
MIGfMA0GCSqGSIb3DQEBAQUAA4GNADCBiQKBgQC+L7ENzBHxKOqjuFHPFKlAt40B
atVZhUAHw/G05XshpTGqm9Rv8wG0EAbFbdo9PuB8DiXdPQLyIfaqkTgpsPjJ1Ow7
WKxmYbqZN5IW/GN+TyFWP+MB2W6IBLPWBDvAl2NJlmU8j3LCPJW1dH4zP1OitkxZ
MyUuUYYfPuOtO9RJ2wIDAQAB
-----END PUBLIC KEY-----';

public $pi_key;
 public $pu_key;

 //判斷公鑰和私鑰是否可用
 public function __construct()
 {
  $this->pi_key = openssl_pkey_get_private($this->private_key);//這個(gè)函數(shù)可用來判斷私鑰是否是可用的，可用返回資源id Resource id
  $this->pu_key = openssl_pkey_get_public($this->public_key);//這個(gè)函數(shù)可用來判斷公鑰是否是可用的
  // print_r($this->pi_key);echo "\n";
  // print_r($this->pu_key);echo "\n";
 }

 //私鑰加密
 /*public function PrivateEncrypt($data){
  openssl_private_encrypt($data,$encrypted,$this->pi_key);
  $encrypted = $this->urlsafe_b64encode($encrypted);//加密后的內(nèi)容通常含有特殊字符，需要編碼轉(zhuǎn)換下，在網(wǎng)絡(luò)間通過url傳輸時(shí)要注意base64編碼是否是url安全的
  return $encrypted;
 }*/

 public function PrivateEncrypt($data){
  // openssl_private_encrypt($data,$encrypted,$this->pi_key);
  $crypto = '';
  foreach (str_split($data, 117) as $chunk) {
   openssl_private_encrypt($chunk, $encryptData, $this->pi_key);
   $crypto .= $encryptData;
  }
  $encrypted = $this->urlsafe_b64encode($crypto);//加密后的內(nèi)容通常含有特殊字符，需要編碼轉(zhuǎn)換下，在網(wǎng)絡(luò)間通過url傳輸時(shí)要注意base64編碼是否是url安全的
  return $encrypted;
 }

//加密碼時(shí)把特殊符號替換成URL可以帶的內(nèi)容
 function urlsafe_b64encode($string) {
  $data = base64_encode($string);
  $data = str_replace(array('+','/','='),array('-','_',''),$data);
  return $data;
 }

 //解密碼時(shí)把轉(zhuǎn)換后的符號替換特殊符號
 function urlsafe_b64decode($string) {
  $data = str_replace(array('-','_'),array('+','/'),$string);
  $mod4 = strlen($data) % 4;
  if ($mod4) {
   $data .= substr('====', $mod4);
  }
  return base64_decode($data);
 }

 //私鑰加密的內(nèi)容通過公鑰可用解密出來
 public function PublicDecrypt($encrypted){
  // $encrypted = $this->urlsafe_b64decode($encrypted);
  $crypto = '';
  foreach (str_split($this->urlsafe_b64decode($encrypted), 128) as $chunk) {
   openssl_public_decrypt($chunk, $decryptData, $this->pu_key);
   $crypto .= $decryptData;
  }
  //openssl_public_decrypt($encrypted,$decrypted,$this->pu_key);//私鑰加密的內(nèi)容通過公鑰可用解密出來
  return $crypto;
 }

 //公鑰加密
 public function PublicEncrypt($data){
  //openssl_public_encrypt($data,$encrypted,$this->pu_key);//公鑰加密
  $crypto = '';
  foreach (str_split($data, 117) as $chunk) {
   openssl_public_encrypt($chunk, $encryptData, $this->pu_key);
   $crypto .= $encryptData;
  }
  $encrypted = $this->urlsafe_b64encode($crypto);
  return $encrypted;
 }

 //私鑰解密
 public function PrivateDecrypt($encrypted)
 {
  $crypto = '';
  foreach (str_split($this->urlsafe_b64decode($encrypted), 128) as $chunk) {
   openssl_private_decrypt($chunk, $decryptData, $this->pi_key);
   $crypto .= $decryptData;
  }
  //$encrypted = $this->urlsafe_b64decode($encrypted);
  //openssl_private_decrypt($encrypted,$decrypted,$this->pi_key);
  return $crypto;
 }
}

不用我多寫什么了吧，有問題可以直接聯(lián)系我。

以上這篇基于PHP RSA密文過長加密解密越過1024的解決方法就是小編分享給大家的全部內(nèi)容了，希望能給大家一個(gè)參考，也希望大家多多支持腳本之家。

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