/*--------------------------------
求2個(gè)或以上字段為NULL 的記錄
t1:
id, id1, id2, id3, id4, id5, id6
在t1 表中有個(gè)字段；
其中id是主鍵；
怎樣打印其中個(gè)字段或以上為NULL 的記錄id？
另外，存儲(chǔ)過(guò)程中怎么實(shí)現(xiàn)按順序一條一條讀取記錄最方便？
注：主鍵id 是沒(méi)有順序的，也可能是字符串的；
-----------------------------------------*/
drop table if exists t1;
create table t1(id int,id1 int,id2 int,id3 int,id4 int,id5 int,id6 int);
insert t1 select
1,1,1,1,1,null,null union all select 
2,null,null,null,1,2,3 union all select 
3,1,2,3,4,5,6 union all select 
4,1,2,3,4,5,null union all select 
5,null,3,4,null,null,null ;
delimiter $$
create procedure usp_c_null()
begin 
declare n_c int;
declare idd int;
declare cur cursor for 
select id,case char_length(concat(ifnull(id1,'@'),ifnull(id2,'@'),ifnull(id3,'@'),ifnull(id4,'@'),ifnull(id5,'@'),ifnull(id6,'@')))
-char_length(replace(concat(ifnull(id1,'@'),ifnull(id2,'@'),ifnull(id3,'@'),ifnull(id4,'@'),ifnull(id5,'@'),ifnull(id6,'@')),'@','') )
 when 6 then 6 when 5 then 5 when 4 then 4  when 3 then 3 when 2 then 2 when 1 then 1 else 0 end as c from t1;
declare exit HANDLER for not found close cur ;
open cur;
repeat 
fetch cur into idd,n_c;
if(n_c>=2) then
select * from t1 where id=idd;
end if ;
until 0 end repeat;
close cur;
end ;
$$
delimiter ;
/*
+------+------+------+------+------+------+------+
| id  | id1 | id2 | id3 | id4 | id5 | id6 |
+------+------+------+------+------+------+------+
|  1 |  1 |  1 |  1 |  1 | NULL | NULL |
+------+------+------+------+------+------+------+
1 row in set (0.10 sec)
+------+------+------+------+------+------+------+
| id  | id1 | id2 | id3 | id4 | id5 | id6 |
+------+------+------+------+------+------+------+
|  2 | NULL | NULL | NULL |  1 |  2 |  3 |
+------+------+------+------+------+------+------+
1 row in set (0.14 sec)
+------+------+------+------+------+------+------+
| id  | id1 | id2 | id3 | id4 | id5 | id6 |
+------+------+------+------+------+------+------+
|  5 | NULL |  3 |  4 | NULL | NULL | NULL |
+------+------+------+------+------+------+------+
1 row in set (0.17 sec)
*/