代碼

#include <iostream>
#include <cstdlib>
#include <memory>
#include <string>
#include <functional>
using namespace std;
class go
{
public:
  go() {}
  ~go()
  {
    cout << "go die.\n";
  }
};
auto d = [] ( go * gp )
{
  delete gp;
  cout << "deletor done.\n";
};
class go_de
{
public:
  void operator() ( go* g )
  {
    d ( g );
  }
};
int main()
{
  {
    unique_ptr < go, go_de > b{ new go{} };//1
  }
  {
    //unique_ptr < go, decltype (d) > b{ new go{}}; complie error //2
    unique_ptr < go, decltype (d) > a{ new go{}, d };//3
  }
  {
    unique_ptr < go, function<void(go*) > > a{ new go{}, d };//4
    //i.e. unique_ptr < go, function<void(go*) > > a{ new go{}, [](go*gp) {delete gp;cout << "deletor done.\n"; }};
  }
  system ( "pause" );
  return 0;
}

描述

一般的，需要給一個(gè)模板的Concept參數(shù)時(shí)，都會(huì)像代碼1的實(shí)現(xiàn)一樣傳入一個(gè)實(shí)現(xiàn)了該Concept的類型，例如go_de就實(shí)現(xiàn)了unique_ptr 的模板參數(shù)Deletor。

今天想嘗試一下使用lambda表達(dá)式的類型作為模板參數(shù)傳入，發(fā)現(xiàn)不行。原因在于

c++14 draft n4269

5.1.2 Lambda expressions

20 The closure type associated with a lambda-expression has no default constructor and a deleted copy assignment operator. It has a defaulted copy constructor and a defaulted move constructor (12.8). [ Note: These special member functions are implicitly defined as usual, and might therefore be defined as deleted. end note ]

意思就是 lambda 表達(dá)式?jīng)]有默認(rèn)的構(gòu)造函數(shù)，operator=也被置為deleted。只有一個(gè)默認(rèn)的復(fù)制構(gòu)造函數(shù)和move構(gòu)造函數(shù)。很顯然，unique_ptr 的實(shí)現(xiàn)肯定是用到了Deletor Concept的默認(rèn)構(gòu)造函數(shù)的。所以編譯不通過(guò)。這個(gè)在
unique_ptr構(gòu)造函數(shù)頁(yè)寫的很清楚。

2) Constructs a std::unique_ptr which owns p, initializing the stored pointer with p and value-initializing the stored deleter. Requires that Deleter is DefaultConstructible and that construction does not throw an exception.2) Constructs a std::unique_ptr which owns p, initializing the stored pointer with p and value-initializing the stored deleter. Requires that Deleter is DefaultConstructible and that construction does not throw an exception.

設(shè)想unique_ptr( pointer p, d1 );構(gòu)造函數(shù)不存在，那Lambda類型就沒(méi)法作為Concept傳入了。

總結(jié)

• 想用Lambda表達(dá)式的類型作為Concept，使用類型推導(dǎo)關(guān)鍵字decltype
• Lambda的類型沒(méi)有default constructor、copy assignment operator.
• 寫C++庫(kù)的時(shí)候，如果用到模板和Concept技術(shù)，要考慮添加Concept對(duì)象做參數(shù)的類型的構(gòu)造函數(shù)從而才能不限制Lambda表達(dá)式類型作為Concept傳入。

畢竟，C++語(yǔ)言設(shè)計(jì)的原則是盡量不限制C++語(yǔ)言的用戶的編程方式。

以上所述是小編給大家介紹的C++ 中使用lambda代替 unique_ptr 的Deleter的方法，希望對(duì)大家有所幫助，如果大家有任何疑問(wèn)請(qǐng)給我留言，小編會(huì)及時(shí)回復(fù)大家的。在此也非常感謝大家對(duì)腳本之家網(wǎng)站的支持！

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